How many 0's are located to the right of the decimal point and before the first non-zero digit in the terminating decimal representation of $\frac{1}{2^5\cdot5^8}$?
25 / 58 = (2/5)5 * (1/5)3 = (4/10)5 * (2/10)3 = [45 * 24] / [108] = 16384/108 ......and the number of leading zeroes will equal [the number of zeroes in the denominator - the number of digits in the numerator] = [8 - 5] = 3 leading zeroes
25 / 58 = (2/5)5 * (1/5)3 = (4/10)5 * (2/10)3 = [45 * 24] / [108] = 16384/108 ......and the number of leading zeroes will equal [the number of zeroes in the denominator - the number of digits in the numerator] = [8 - 5] = 3 leading zeroes
+1836 
