#2**+1 **

From 1 to 9 none

From 10 to 99 there are 9

Now I will look at numbers from 100 to 999 =

zero in the middle but not at end = 9*1*9 = 81

zero at the end but not in middle = 9*9*1 = 81

zero in middle and at end = 9*1*1=9 numbers that is 18 zeros

Total for 2 digit numbers = 9+81+81+18 = **189**

Now look at numbers 1000 to 1999

2 zeros = 1*9*3C2 = 9*3 = 27numbers = 54 zeros

3 zeros = 1number = 3 zeros

1 zero = 1*9*9 = 81 zeros **Edit: I forgot to times this by 3 243**

2000 has 3 zeros

Total for 3 digit numbers is 54+3+243+3 = 303

**Grand total appears to be 189+303 = 492 (I did not include 2001)**

Thanks Guest :)

Melody Oct 20, 2019

#3**+1 **

**From 1 to 9 =None From 10 to 99 = 9 From 100 to 199 =20 From 200 to 999 =160 From 1000 to 1999 =300 From 2000 to 2001(inclusive) =5 Grand Total = 9 + 20 + 160 + 300 + 5 =494 zeros**

**P.S. If you don't want 2001 included, then:494 - 2 =492 zeros.**

Guest Oct 20, 2019

edited by
Guest
Oct 20, 2019

#4**+1 **

The only part where our answers differ ( i think) is that

from 1000 to 1999

you got 300

I got 141

I will check what i did

3 zero numbers is just 1000 so that is **3 zeros**

2 zero numbers the none zero can be in the 2nd 3rd or 4th place that is 3 permutations

so there will be 100* = 1*1*1*9 *3 = 27numbers = **54 zeros**

1 zero numbers

1**0 the zero can be in 3 places so

there will be 1*9*9*1*3 = 243 numbers totalling **243 zeros**

**so that is 3+54+243 = 300**

**Just like guest said - so now we are in agreement **

Melody
Oct 20, 2019