How many children were you?

Let S = sisters, B = brothers and FC = first cousins.....and we're told that.......

S = 3FC

S = 2B

So

B = (3/2)FC

And let "me"  = 1

So

3FC + (3/2)FC + 1  < 19

3FC + (3/2)FC < !8 

(4.5)FC  < 18

FC < 4  

But....FC has to be a multiple of 2, because if it's an odd number, the number of brothers will be a fractional amount.....!!!!!

But if FC < 4, then the only multiple of two is 2...!!!

So FC =2

S = (3)FC = 3(2) = 6

B = (3/2)FC = (3/2)(2)  = 3

So....the total children =  6 sisters, 3 brothers  (and "me")  = 10

My mother had 8 kids, but 5 of them died :( 😢😣

My brother, sister and I were the only survivors...

THIS IS TRUE!!!

Well, your mum had less than 19 children.

Since you have 3 times more sisters than cousins it stands to reason that you have at least one cousin.

Lets do a table

So my mum had 10 children          [Corrected - I forgot me, even though I was in the table  LOL]

To all answerers.

This table fuction is built into the web 2 forum.  

It does not do borders which is a pity but it is a great feature and I seem to be the only one that ever uses it.  Why is that?

I have added this to our logic puzzle thread. (in sticky threads) :)

Thank you anon for providing it :)

Thanks Chris

You make it look so difficult Chris.   

Just proves, Melody....you need to stay away from "tables"....LOL!!!!