How many children were you?

If you ask me such a question, I will reply that my mother dreamed of having at least 19 children but her dream did not come true, that my sisters were three times as more numerous than my first cousins, and that I had half as many brothers as I had sisters.

Guest May 13, 2015

#5**+8 **

Let S = sisters, B = brothers and FC = first cousins.....and we're told that.......

S = 3FC

S = 2B

So

B = (3/2)FC

And let "me" = 1

So

3FC + (3/2)FC + 1 < 19

3FC + (3/2)FC < !8

(4.5)FC < 18

FC < 4

But....FC has to be a multiple of 2, because if it's an odd number, the number of brothers will be a fractional amount.....!!!!!

But if FC < 4, then the only multiple of * two is 2*...!!!

So FC =2

S = (3)FC = 3(2) = 6

B = (3/2)FC = (3/2)(2) = 3

So....the total children = 6 sisters, 3 brothers (and "me") = 10

CPhill
May 14, 2015

#1**+8 **

My mother had 8 kids, but 5 of them died :( ðŸ˜¢ðŸ˜£

My brother, sister and I were the only survivors...

THIS IS TRUE!!!

GirlsNightOut
May 13, 2015

#2**+13 **

Well, your mum had less than 19 children.

Since you have 3 times more sisters than cousins it stands to reason that you have at least one cousin.

Lets do a table

Me | first cousins | sisters | brothers | Total |

1 | 1 | 3 | 1.5 that's a bit difficult | |

1 | 2 | 6 | 3 | 10 |

1 | 3 | 9 | 4.5 X | |

1 | 4 | 12 | 6 | 19 Too many |

So my mum had 10 children [Corrected - I forgot me, even though I was in the table LOL]

Melody
May 14, 2015

#3**+5 **

To all answerers.

**This table fuction is built into the web 2 forum. **

It does not do borders which is a pity but it is a great feature and I seem to be the only one that ever uses it. Why is that?

Melody
May 14, 2015

#4**+8 **

I have added this to our logic puzzle thread. (in sticky threads) :)

Thank you anon for providing it :)

Melody
May 14, 2015

#5**+8 **

Best Answer

Let S = sisters, B = brothers and FC = first cousins.....and we're told that.......

S = 3FC

S = 2B

So

B = (3/2)FC

And let "me" = 1

So

3FC + (3/2)FC + 1 < 19

3FC + (3/2)FC < !8

(4.5)FC < 18

FC < 4

But....FC has to be a multiple of 2, because if it's an odd number, the number of brothers will be a fractional amount.....!!!!!

But if FC < 4, then the only multiple of * two is 2*...!!!

So FC =2

S = (3)FC = 3(2) = 6

B = (3/2)FC = (3/2)(2) = 3

So....the total children = 6 sisters, 3 brothers (and "me") = 10

CPhill
May 14, 2015