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# How Many complete pieces can be blanked from a strip of aluminum 72 inches long if each stamping requires 1/3/8 inches of material plus an a

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How Many complete pieces can be blanked from a strip of aluminum 72 inches long if each stamping requires 1/3/8 inches of material plus an allowance of 3/4 inches at one end of the strip?

Jun 5, 2014

#1
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If I'm reading this right, we need 3/4 space allowed on each end that can't be used for stamping, and each stamping requires an area of 1 over 3/8 inches. How many will fit in a 72 inch strip?

I think this is how to solve it...

3/4+3/4+11/8(n) = 72

6/4+11/8(n) = 72

1.5+1.375(n) = 72

-1.5               -1.5     -Subtract 1.5 from both sides

1.375(n) = 70.5

/1.375      /1.375    -Divide both sides by 1.375

n = 51.272727

It asked for complete strips, so a total of 51 complete strips can be made out of this peice of aluminum.

Let's check it:

1.5+1.375(n) = 72

1.5+1.375(51.272727) = 72

71.999999999 ~= 72

Jun 5, 2014

#1
+5

If I'm reading this right, we need 3/4 space allowed on each end that can't be used for stamping, and each stamping requires an area of 1 over 3/8 inches. How many will fit in a 72 inch strip?

I think this is how to solve it...

3/4+3/4+11/8(n) = 72

6/4+11/8(n) = 72

1.5+1.375(n) = 72

-1.5               -1.5     -Subtract 1.5 from both sides

1.375(n) = 70.5

/1.375      /1.375    -Divide both sides by 1.375

n = 51.272727

It asked for complete strips, so a total of 51 complete strips can be made out of this peice of aluminum.

Let's check it:

1.5+1.375(n) = 72

1.5+1.375(51.272727) = 72

71.999999999 ~= 72