How many different primes appear in the prime factorization of \(20!\) (20 factorial)? (Reminder: The number \(n!\) is the product of the integers from 1 to \(n\) . For example: \( 5!=5\cdot 4\cdot3\cdot2\cdot 1= 120\)

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just find how many primes are from 1 to 20. These are 2, 3, 5, 7, 11, 13, 17, and 19, which is 8 primes