Haha sorry guys. Now a bunch of Pascal's Triangle questions. Not probability. But they WILL come back
Actually.....I believe 91 will appear 4 times in the triangle.....
The entries are C(14,2), C (14,12), C(91,1) and C(91,90)
I think that's it !!!!
Chris is correct. I didn't account for the C(91,1) and C(91,90) values.
I actually wrote a little program that ran through values of n and, for each n, tried values of k from 1 to n to find those combinations for which C(n,k) = 91. However, I stopped short of n = 91. Silly!
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