+0

# How many integers are there on the number line between $\dfrac{17}{3}$ and $\left(\dfrac{17}{3}\right)^2$?

0
294
2

How many integers are there on the number line between $\dfrac{17}{3}$ and $\left(\dfrac{17}{3}\right)^2$?

Apr 8, 2020

#1
-1

$$\frac{17}{3}\approx6$$

$$(\frac{17}{3})^2\approx32$$

$$32-6=26$$

There are 26 integers between $$\frac{17}{3}$$ and $$(\frac{17}{3})^2$$

-Ako

Apr 8, 2020
#2
+1

Ako, I understand your process, but the last part of arithmetic is wrong.

We know that the first term in the sequence in numbers between is 17/3 which's ceiling is 6, and (17/3)^2, which's floor is 32.

The sequence is as follow:

(6, 7, 8, ...., 30, 31, 32)

So we have to find the number of terms between 6 and 32 inclusive, which is 32 - 6 + 1 and that is 27, we have to do this because subtraction only includes 1 of the values not both of them.

Or we could've done it by subtracting 5 from every term in the sequence then you would get:

(6-5, 7-5, 8-5, ...., 30-5, 31-5, 32-5)

(1, 2, 3, ..., 25, 26, 27)

Either way you can see that there are 27 terms, so the answer is 27 integers. KingHTML  Apr 8, 2020