+92 Since this is a compound, we need to find the molar masses of each element and add them all together.
Fe = 55.845 x 3 = 167.535
P = 30.974 x 2 = 61.948
O = 15.999 x 8 = 127.992
And all of adds together to 357.475, which will be the molar mass for iron (II) phosphate (or Fe3(PO4)2). So now we just divide the mass by the molar mass.
130.17 g / 357.475 g/mol = 0.3641373523 mol Fe3(PO4)2
And then the significant figures come into play again. We have five figures this time.
0.36414 mol Fe3(PO4)2
+92 Since this is a compound, we need to find the molar masses of each element and add them all together.
Fe = 55.845 x 3 = 167.535
P = 30.974 x 2 = 61.948
O = 15.999 x 8 = 127.992
And all of adds together to 357.475, which will be the molar mass for iron (II) phosphate (or Fe3(PO4)2). So now we just divide the mass by the molar mass.
130.17 g / 357.475 g/mol = 0.3641373523 mol Fe3(PO4)2
And then the significant figures come into play again. We have five figures this time.
0.36414 mol Fe3(PO4)2
