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Read the title to see the problem

 Aug 13, 2024
 #1
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Alright, first let's note that we can caluclate the number of distinct arrangements through the equation

\(\text{Number of Distinct Arrangements} = \frac{n!}{n_1! \cdot n_2! \cdot n_3! ... \cdot n_k!}\)

 

where n is the total number of items to arrange, and n1,n2,…,nk are the frequencies of the distinct items (for example, i in mississippi appears 4 times). 

 

Thus, let's list our the letters we have in the word. 

Mississippi has 11 letters, so n is 11. 

In the word, i appears 4 times, m appears once, s appears twice, and p appears twice. 

 

Thus, plugging in all these numbers, we have

\(\frac{11!}{1! \cdot 4! \cdot 2! \cdot 21} = 34650\)

 

So 34650 is our answer. 

 

Thanks! :)

 Aug 13, 2024
edited by NotThatSmart  Aug 13, 2024

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