How many sides does the regular polygon have if each exterior angle measure is one eighth the measure of each interior angle measure?

Exyterior angle of a regular n-sided polygon = 360°/n

Interior angle = 180° - 360°/n

So, with 360/n = (1/8)(180 - 360/n)

360/n = 180/8 - 360/(8n)

(360/n)*(9/8) = 180/8

2*9/n = 1

n = 18

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Hmmmm...maybe this will help: