+0  
 
0
84
6
avatar+251 

How many solutions are there to the equation u+v+w+x+y+z where u,v,w,x,y  and z  are nonnegative integers?

 Sep 18, 2022
 #1
avatar+2448 
+1

that's not an equation...

 Sep 18, 2022
 #2
avatar+251 
+1

Does it not say =6 at the end?. On my screen it says u+v+w+x+y+z=6

Jasonkiln  Sep 18, 2022
 #3
avatar+2448 
0

It doesn't on my end...

 

BuilderBoi  Sep 19, 2022
 #4
avatar+2448 
+1

Use stars and bars. 

 

There are 6 stars and 4 bars for \({6 + 4 \choose 4} = {10 \choose 4} = \color{brown}\boxed{210}\)

 Sep 19, 2022
 #5
avatar+251 
0

210 is incorrect according to the system.

 Sep 19, 2022
 #6
avatar+284 
+1

There are actually 6 stars and 5 bars, as there are 6 of these integers. You should be able to sovle the problem now, Builderboi just made a tiny error. 

 Sep 19, 2022

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