How many times would a mole of shoe strings (16cm long) stretch from Earth to the moon?
Holy Moley......!!!!! ......not just CDD, Nauseated.....but a case of "LUNA-cy," as well.........!!!
I have personally commissioned one your academy "grads" to double-check Alan's answer....I think I also mentioned something to him about keeping an eye out for a certain "Roman Zero" - (if he happens across it somewhere in deep space...)
16*15755= 252,080... The distance from Earth to moon is 252,088 so 252,080 is 8 less... So you would add half a mole of shoe string to it.... So times 16 by 15755 and then add 8 and there you have it. :)
Good effort notthebestmathmaster 😀
I am on my phone and not checking properly but I think you have determined that 15755.5 shoe strings are needed.
The question actually asked how many moles of shoe strings ard needed.
I do not know how many shoe strings are in a mole but you would need to divide the answer by this number. ☺
Well, We have our first official case of CDD for the new year. It looks like a major outbreak, too!
A mole of shoe strings would be Avogadr's number of shoe strings, namely, 6.02214129x1023 shoe strings.
The total length of this lot stretched end to end would be 0.00016*6.02214129x1023 km long.
The distance from Earth to Moon is 384400 km, so the number of times the shoe strings would stretch between them is:
$${\frac{{\mathtt{0.000\: \!16}}{\mathtt{\,\times\,}}{\mathtt{6.022\: \!141\: \!29}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{23}}}}{{\mathtt{384\,400}}}} = {\mathtt{250\,661\,448\,074\,921.956\: \!295\: \!525\: \!494\: \!276\: \!8}}$$
or about 251 trillion times!
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Holy Moley......!!!!! ......not just CDD, Nauseated.....but a case of "LUNA-cy," as well.........!!!
I have personally commissioned one your academy "grads" to double-check Alan's answer....I think I also mentioned something to him about keeping an eye out for a certain "Roman Zero" - (if he happens across it somewhere in deep space...)