Spirytus Polish Vodka is 96% alcohol by volume.
How much cranberry juice (no alcohol content) would have to be added to 500mL of this vodka to give the resultant mixture with an alcohol content of 12%?
Volume of alcohol = 0.96*500 mL
Total volume = 500 + C where C is volume of cranberry juice
0.96*500/(500 + C) = 0.12
0.96*500 = 0.12*(500 + C)
0.96*500/0.12 = 500 + C
C = 0.96*500/0.12 - 500
$${\mathtt{C}} = {\frac{{\mathtt{0.96}}{\mathtt{\,\times\,}}{\mathtt{500}}}{{\mathtt{0.12}}}}{\mathtt{\,-\,}}{\mathtt{500}} \Rightarrow {\mathtt{C}} = {\mathtt{3\,500}}$$
So you must add 3500 mL of cranberry juice.
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Spirytus Polish Vodka is 96% alcohol by volume.
How much cranberry juice would have to be added to 500mL of this vodka resultant mixture with an alcohol content of 12%
Volume of alcohol= 0.96 x 500mL
Total Volume: 500+C, where C is volume of cranberry juice
0.96 x 500/(500 + C) = 0.12
0.96 x 500 = 0.12 x ( 500 + C)
0.96 x 500/0.12 - 500= 3500
So you must add 3500 mL of cranberry juice
b. How much Smirnoff Vodka with an alcohol content of 37.5% by volume would have to be added to 500mL of Smirnoff Vodka to get a resultant mixture of 55% alcohol.