the brothers age is twice his sisters. in 6 years the brothers age will 5 times his sister age as she was 3 years ago. how old are they today?
Let's have b = current brother's age and s = current sister's age.
The brothers age is twice his sisters age, so we have:
b = 2s
In 6 years, the brothers age will be 5 times his sisters age...as she was 3 years ago.
6 + b = 5(s-3) ---Now just simplify a little bit
6 + b = 5s - 15
21 + b = 5s
So how we have two equations.
b = 2s
and
21 + b = 5s
Let's solve this by elimiation. Multiply the first equation by a negative
b = 2s
-b = -2s
21 + b = 5s ---Second equation
21 = 3s
7 = s
The sisters age is 7. Let's put in this for s in the first equation and solve for b (which is the brothers age)
b = 2s
b = 2(7)
b = 14
So the sister is 7 years old and the brother is 14 years old.
Let's have b = current brother's age and s = current sister's age.
The brothers age is twice his sisters age, so we have:
b = 2s
In 6 years, the brothers age will be 5 times his sisters age...as she was 3 years ago.
6 + b = 5(s-3) ---Now just simplify a little bit
6 + b = 5s - 15
21 + b = 5s
So how we have two equations.
b = 2s
and
21 + b = 5s
Let's solve this by elimiation. Multiply the first equation by a negative
b = 2s
-b = -2s
21 + b = 5s ---Second equation
21 = 3s
7 = s
The sisters age is 7. Let's put in this for s in the first equation and solve for b (which is the brothers age)
b = 2s
b = 2(7)
b = 14
So the sister is 7 years old and the brother is 14 years old.