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There were some marbles in Box A and Box B.

Joel took out \( {1 \over 9}\) of the marbles from Box A and put

all of them into Box B. The ratio of the number of 

marbles in Box A to the number of the marbles in

Box B became 4 : 7. There were then 42 more

marbles in Box B than in Box A. How many 

marbles were there in Box B at first?

 Oct 5, 2021
edited by Guest  Oct 5, 2021
 #1
avatar+35058 
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removing 1/9 from A   leaves 8/9 A   left in A
 

8/9 A  / (B + 1/9 A)   = 4/7            Then   given that   B+ 1/9 A  =  42 + 8/9 A     sub this in for  ( B +  1/9 A)

 

8/9 A / (42 +8/9 A) = 4/7               

8/9 A = 4/7 ( 42 + 8/9 A)                         reults in A = 63    then because  B+ 1/9 A  =  42 + 8/9 A        B = 91 marbles originally

 Oct 5, 2021

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