how do we find the first 40 positive integers divisible by 6?
When we want to find integers divisible by x (x=integer) we want to find integers of the form x*n when n is an integer as well.
Try it now, and let me know if you solved it
6 is divisble by 6. 6=6*1
12 is divisble by 6. 12=6*2
18 is divisble by 6. 18=6*3
34545674756345453.34543575 is not divisble by 6, because (34545674756345453.34543575)/6 is not an integer
21 is not divisble by 6, because 21/6 is not an integer.
im sorry, i dont want to give you the answer, i want YOU to get to the final answer
ok i get the first part. but how do we find the last(40th) positive integer divisible by 6?
If we know that when n is an integer 6*n is divisble by 6 starting with 1, and we want to find 40 integers that are divisble by 6 then for the last integer n will be........?
my mistake- instead of "starting with 1" it should be "starting with n=1"