+0

# how to find the sin cos and tan of 300 degrees?

0
954
1

how to find the sin cos and tan of 300 degrees?

Guest Jul 13, 2015

#1
+17711
+5

Place it on a graph in quadrant IV.

The reference angle (the angle formed with the x-axis) is 60°.

The side opposite the 60° angle has value -√(3)/2.

The side adjacent the 60° angle has value 1/2.

The hypotenuse has value 1.

sin(300°)  =  opposite side / hypotenuse  =  (-√(3)/2) / 1  =  -√(3)/2.

cos(300°)  =  adjacent side / hypotenuse  =  (1/2) / 1  =  1/2.

tan(300°)  =  opposite side / adjacent side  =  (-√(3)/2) / (1/2)  =  -√(3)/2.

geno3141  Jul 13, 2015
Sort:

#1
+17711
+5

Place it on a graph in quadrant IV.

The reference angle (the angle formed with the x-axis) is 60°.

The side opposite the 60° angle has value -√(3)/2.

The side adjacent the 60° angle has value 1/2.

The hypotenuse has value 1.

sin(300°)  =  opposite side / hypotenuse  =  (-√(3)/2) / 1  =  -√(3)/2.

cos(300°)  =  adjacent side / hypotenuse  =  (1/2) / 1  =  1/2.

tan(300°)  =  opposite side / adjacent side  =  (-√(3)/2) / (1/2)  =  -√(3)/2.

geno3141  Jul 13, 2015

### 7 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details