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point # 1 = (x1,y1)
x1 = 0
y1 = 50

point # 2 = (x2,y1)
x2 = 0
y1 = 25

point # 3 = (x2,y2)
x2 = 75
y2 = 25

OPP = ABS(x1-x2)
ADJ = ABS(y1-y2)

TAN(T) = OPP/ADJ

T = (OPP/ADJ)(1/TAN)

How do I calculate the Theata ? Am I heading in the right direction ?
 Jan 28, 2014
 #1
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0
the-ate-tah:

point # 1 = (x1,y1)
x1 = 0
y1 = 50

point # 2 = (x2,y1)
x2 = 0
y1 = 25

point # 3 = (x2,y2)
x2 = 75
y2 = 25

OPP = ABS(x1-x2)
ADJ = ABS(y1-y2)

TAN(T) = OPP/ADJ

T = (OPP/ADJ)(1/TAN)

How do I calculate the Theata ? Am I heading in the right direction ?



Hi the-ate-tah,

First make sure your calculator is in degrees mode. There should be a tiny little D at the top of the screen.
Now,
I am not sure if you are heading in the right direction because I am not sure what you are trying to do.
Now, I have drawn a pretty little picture to show you what I think that you are trying to do.
When you get to
tan theta = 3
It is the angle that you have to find. If you want to find an angle you have to press shift or inv or 2nd to bring up the correct function.
so press
2nd tan 3 and then if you want to get it into degress , minutes and seconds you will need to press the 0 ' " button.

The way I have done it T and theta refer to the same angle.
You can't just separate tan from the angle the way you have done it. It doesn't work that way. they stay together until the very end when you get the value of T from the calculator.

140128 coordinate geometry triangle.JPG
 Jan 28, 2014

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