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;-; such confuse

math algebra
 Aug 11, 2014

Best Answer 

 #1
avatar+4473 
+8

2x/3(y^-1) --> You can move the y^-1 on top --> 2xy/3.

 Aug 11, 2014
 #1
avatar+4473 
+8
Best Answer

2x/3(y^-1) --> You can move the y^-1 on top --> 2xy/3.

AzizHusain Aug 11, 2014
 #2
avatar+118680 
+5

I just did a page of LaTex for this (which I lost) and I am not going to repeat it BUT

Here is a page that I put together on negative indices.  It should help you understand how it works.

http://web2.0calc.com/questions/indices-especially-negative-indices

 

Very simplistically,

If something is raised to a negative indice you swap it to the other side of the fraction line and change the negative index to a positive index.

Also do you mean

2x/3(y^-1)   which means     $$\frac{2x}{3}\times y^{-1}$$

or do you mean

2x/(3(y^-1))  which means   $$\frac{2x}{3y^{-1}}$$

 

You need to learn to use brackets so that your meaning is unmistakable!

 Aug 12, 2014

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