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How to solve this equation? 

Guest Dec 2, 2017
 #1
avatar+7322 
+1

How to solve this equation?

\( {3^{2}}^x+3^x-2=0\)

 

\({3^{2}}^x+3^x-2=0\\ 3^{(2^x)}+3^x=2\\ 3^{(2^x)}=2-3^x \)

\(2^x\times ln\ 3=ln\ (2-3^x)\)

?

Excuse me!

crying

asinus  Dec 2, 2017
edited by asinus  Dec 2, 2017
edited by asinus  Dec 2, 2017
 #2
avatar+26722 
+3

This requires a numerical solution method.  Draw a graph first to see where the solution(s) might lie.

 

.

Alan  Dec 2, 2017
 #3
avatar+12561 
+2

Agree with asinus....graphical method is easiest....here is my result from desmos calculator:

 

 

ElectricPavlov  Dec 2, 2017
 #4
avatar+1048 
+1

Humm ... I might need to slow down on the fermented bananas, I didn’t notice any mention of a graphical method by Asinus. 

 

The graphical method may be the easiest when you are using a computerized graphing tool that iterates the value of (x) over a range that includes y=0.   

Do it with graphing paper; calculate each plotted point with a calculator (or a slide rule) and then explain how it’s easier.indecision    

 

 

GA

GingerAle  Dec 2, 2017
edited by GingerAle  Dec 2, 2017
 #5
avatar+92625 
+1

Hi Ginger,

Graphing it  is easier because than asinus's method becasue asinus never got an answer.

He just re-arranged it a little and then realized that he didn't know how to solve it. 

Melody  Dec 2, 2017

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