#1**+3 **

\(\frac{-2(5x^3y^2)^2}{10xy}\)

Fisrt, distribute the square.

\(\frac{-2(25x^6y^4)}{10xy}\)

Distirbute the -2.

\(\frac{-50x^6y^4}{10xy}\)

Consider that a variable without a power is the same as that variable to the power of 1: x = x^{1}

If a variable with a power is divide by the same variable with a lower power, the powers subtract: x^{6}/x^{3}=x^{6-3}=x^{3}

Simplify.

-50/10=-5

\(\frac{-5x^6y^4}{x^1y^1}\)

Subtract powers.

\(-5x^5y^3\)

AdamTaurus
Oct 18, 2017

#1**+3 **

Best Answer

\(\frac{-2(5x^3y^2)^2}{10xy}\)

Fisrt, distribute the square.

\(\frac{-2(25x^6y^4)}{10xy}\)

Distirbute the -2.

\(\frac{-50x^6y^4}{10xy}\)

Consider that a variable without a power is the same as that variable to the power of 1: x = x^{1}

If a variable with a power is divide by the same variable with a lower power, the powers subtract: x^{6}/x^{3}=x^{6-3}=x^{3}

Simplify.

-50/10=-5

\(\frac{-5x^6y^4}{x^1y^1}\)

Subtract powers.

\(-5x^5y^3\)

AdamTaurus
Oct 18, 2017