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-2(5x^3y^2)^2/10xy

Guest Oct 18, 2017

Best Answer 

 #1
avatar+771 
+3

\(\frac{-2(5x^3y^2)^2}{10xy}\)

Fisrt, distribute the square.

\(\frac{-2(25x^6y^4)}{10xy}\)

Distirbute the -2.

\(\frac{-50x^6y^4}{10xy}\)

Consider that a variable without a power is the same as that variable to the power of 1: x = x1

If a variable  with a power is divide by the same variable with a lower power, the powers subtract: x6/x3=x6-3=x3

Simplify.

-50/10=-5

\(\frac{-5x^6y^4}{x^1y^1}\)

Subtract powers.

\(-5x^5y^3\)

AdamTaurus  Oct 18, 2017
 #1
avatar+771 
+3
Best Answer

\(\frac{-2(5x^3y^2)^2}{10xy}\)

Fisrt, distribute the square.

\(\frac{-2(25x^6y^4)}{10xy}\)

Distirbute the -2.

\(\frac{-50x^6y^4}{10xy}\)

Consider that a variable without a power is the same as that variable to the power of 1: x = x1

If a variable  with a power is divide by the same variable with a lower power, the powers subtract: x6/x3=x6-3=x3

Simplify.

-50/10=-5

\(\frac{-5x^6y^4}{x^1y^1}\)

Subtract powers.

\(-5x^5y^3\)

AdamTaurus  Oct 18, 2017

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