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A train 75 meters long overtook a person who was walking in the same direction at a speed of 6 km/hr and passed him within 15 seconds .Subsequently, it overtook a second person walking in the same direction ans passes him within 7.5 seconds. At what rate was the second person travelling ?

 Jul 26, 2020
 #1
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Since the train passed the first walker in 15 seconds walking at 6 km/h, it therefore follows that the second walker, who was passed in 1/2 the time of the first walker, must be walking at Twice the speed of the first walker, or: 2 x 6 km/h =12 km/h

 Jul 26, 2020
 #2
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.075 km / (x -6) = 15

x = 24 k/hr  is the speed of the train

 

If the person was standing still

  the time required would be     .075/24 x 3600 = 11.25 seconds    so for the train to pass in 7.5 seconds, the person must be walking TOWARD the train

    so walking the same direction as the train at 6 k/hr   takes 15 seconds

        standing still takes  11.25 seconds

            the second person has to be walking TOWARD the train for the train to pass in 7.5 seconds

                and they have to be walking at a rate of   .075/(24+x ) = 7.5/3600    x=12 km/hr    TOWARD the train !!!!

 Jul 28, 2020

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