+1995 I need to create and equation that approximates my data for this sinusidal equation , how would I create one? I know it will have to begin with y=
+129852 No clue, Jenny....did your instructor point you to any technology that might be used to do this???.....
+1995 Well actually this is a sample , I was unsure how they found out the period was 12 , why it was pi/6 , as well as why they changed 25 to negatitive in order to be that equation from the table above.
+1995 sorry for the confusion , hopefully i explained it better where im confused
+118677 The period is 12 because there are 12 months in a year.
The lowest temp is 40 degrees in January
The highest is 89 in july (6 months later)
The average of these is (40+89)/2 = 129/2 = 64.5
89-64.5 = 24.5
y=-24.3cos(nx)
12=2pi/n
n=12/(2pi) = 6/pi
\(y= -24.5 cos \frac{\pi x}{6}+64.5 \qquad\text{The angle is in radians}\\\)
Here is the graph
Oh dear this is meant to be a sinusoidal graph.
The sine curve is just this with a phase shift of a quarter of a period (3 months)
\(y= -24.5 cos \frac{\pi x}{6}+64.5 \qquad\text{The angle is in radians}\\ y= -24.5 sin \frac{\pi }{6}(x+3)+64.5 \\ or\\ y= 24.5 sin \frac{\pi }{6}(x-3)+64.5 \)
Here are the graphs
+1995 im not quite sure where you got the 64.5? Your equation looks a bit different from the example.
+118677 The middle of summer is the top of the sine curve - that is july 89 degrees
The middle of winter is the bottom of the curve -that is Jan 40 degrees
The middle of the curve is the average of these. (89+40)/2 = 129/2 = 64.5
+1995 I posted another question on y profile called " Pleas explain how they got these values" ,I am very confused.
