how would i go about solving 2(x-3)^2 -8=0? without using the quadratic formula?

2(x+3)^2=8

(X+3)^2=4

X+3=2. Or   x+3=-2

X=-1.     Or    x=-5

2(x-3)^2 -8=0   divide through by 2

(x - 3)^2  - 4  = 0       factor as   a difference of squares

[ (x - 3) + 2]  [ (x - 3)  - 2]  = 0

[ x - 1]  [ x - 5]  = 0      and setting each factor to 0 , x =  1  or x = 5

Rats....!!!....Melody beat me to it........!!!!!!!

[ She probably cheated......LOL!!!!!]

TWO COMPETITIVE ANSWERS!

But mine was MORE competitive, DS.......!!!!!!!

Hey guys: are the answers positive or negative?

Melody copied the problem  wrong......I WIN   !!!!!!!!

Mine is correct guest.....

Hey Melody: Both answers should be POSITIVE!!.

Ahh! Melody was captured cheating! JESUS!

LOL!

I didn't cheat DS,

I just answered the wrong question - But I got it right  LOL     :))

Yep I answered on my phone.  I make much more mistakes on my phone.

The fault is the stupid little screen. IT IS NOT MY FAULT!!!       LOL

BUT STILL

I got my question right !!!