How would you calculate the probability of rolling a single die 11 times and getting all of the numbers at least once.
Thank you for the answer, but how do you come to that answer.
I'm not entirely sure how to calculate it, but there is a way to visualise the solution. Picture 6 dice, each with a different number on it. These collectively represent the first die. Then draw 6 lines from each of those, at the end of which are 6 dice per original die, each with their own unique number from 1-6. They represent the second thrown die. Do this 9 more times, and you will have graphically represented each and every possible outcome of rolling 11 dice in a row (exactly 6^11 outcomes). Now, all you need to do is look at each one, and determine x/(6^11), where x is how many of thoise outcomes fit the original conditions. I definitely don't have the time to do all that, but it's the only way I can think of to calculate those conditions.
Sorry if this doesn't help...
