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# Hyperbola Ebola

+2
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+90

Write the equation of the hyperbola described below

center(3,3) ,focus(8,3), vertex (6,3)

Remember please put in the steps as well!

Thank you!!!

dom6547  Apr 2, 2018
edited by dom6547  Apr 2, 2018
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#1
+333
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Since the center, focus, and vertex all lie on the line $$y=3$$, the hyperbola opens left/right. This means that we use this form:

$${(x-h)^2\over a^2}-{(y-k)^2\over b^2}=1$$

Now, we substitute the values as follows:

1. h is the x-coordinate of the center

2. k is the y-coordinate of the center

3. a is the distance from the center to the vertex

4. b2 = c2 - a2, wherein c is the distance from the center to the focus

Which means:

1. $$h=3$$

2. $$k=3$$

3. $$a=\sqrt{(3-6)^2+(3-3)^3}=3$$

4. $$c=\sqrt{(3-8)^2+(3-3)^2}=5$$$$b^2=25-9=16$$

Substituting, we get $${(x-3)^2\over9}-{(y-3)^2\over16}=1$$, and that is your equation.

Mathhemathh  Apr 3, 2018
#2
+90
+2

Thank you I am cured!!!

dom6547  Apr 3, 2018

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