The parabola \(y = x^2+2\) and the hyperbola \(y^2 - mx^2 = 1\) are tangent. Find \(m.\)

Guest Mar 9, 2019

#1**+1 **

Hyperbolas and parabolas are not tangents. That makes no sense.

I assume you mean that they only touch each other in one place. Which means they have only one simultaneous solution.

I would try making x^2 the subject of the formula for the first equation.

then

substitute this value of x^2 inot the second equation.

then

solve the new equation as an quadratic. You may then have 2 values for y (in terms of m)

and

etc

Try that and get back with what you have done.

** No one answer over me. Thanks **

Melody Mar 9, 2019