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Two long strips of paper are each 2 inches wide, and they overlap so that the angle between the strips is $30^{\circ}$. What is the number of square inches in the area of the parallelogram formed by the overlap?

I got 4 but it was wrong...

 Mar 8, 2021
 #1
avatar+31195 
+2

Drop a line from intersection

  sin 30 = opposite/hyp

      .5  = 2/hyp

     hyp = 2/.5 = 4     = side lengths of parallelogram

           height = 2

 

4 x 2 = 8 in2

 

 

 Mar 8, 2021
 #2
avatar+54 
0

Thanks

qwertyytrewq  Mar 8, 2021

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