+73 Two long strips of paper are each 2 inches wide, and they overlap so that the angle between the strips is $30^{\circ}$. What is the number of square inches in the area of the parallelogram formed by the overlap?
I got 4 but it was wrong...
+37146 Drop a line from intersection
sin 30 = opposite/hyp
.5 = 2/hyp
hyp = 2/.5 = 4 = side lengths of parallelogram
height = 2
4 x 2 = 8 in2
