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# I am in need of assistance

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Rewrite the expression as a single logarithm . Then the function

$$\log_2 x + 5 \log_2 y -3 \log_2 z$$

Rewrite the expressionas a single logarithm . Then the function

$$\ln (a+b) + 4 \ln (a-b) - 3 \ln c$$

Rewrite the expression as a single logarithm . Then the function

$$5 \log x - 4 \log (x^2+1) +2 \log (x-1)$$

Jun 6, 2018

### 2+0 Answers

#1
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logx  + 5 log2 y  - 3 log 2 x  =

log2 x  + log2 y - log2 x3 =

log2  [ ( x y5 ) / x3 ] =

log2 [ y5 / x2 ]

ln ( a + b)  + 4 ln ( a - b) - 3 ln c  =

ln (a + b) + ln ( a - b)4  - ln c3 =

ln  ( [ (a + b) (a - b)4 ] / c3 )

5 log x - 4 log (x2 + 1)  + 2 log (x - 1)  =

log x5  - log (x2 + 1)4 + log ( x - 1)2   =

log   [   (x5 * (x - 1)2 ) / (x2 + 1)4  ]

Jun 6, 2018
#2
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A small typo in the first one. It should read:

Log_2[xy^5 / z^3]

Jun 6, 2018