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If two lines l and m have equations y = -x + 6, and y = -4x + 6, what is the probability that a point randomly selected in the 1st quadrant and below l will fall between l and m? Express your answer as a decimal to the nearest hundredth.

I have tried doing the area of success over possible and I knwo the possible is 81 becuase 9*9. I cant figure out the rest. please hepl

 Jun 17, 2020
 #1
avatar+22071 
+1

The possible is the area of the triangle bounded by the x-axis, the y-axis, and the line y = -x + 6.

The endpoints of this triangle are (0,0), (6,0), and (0,6)  [Sorry; it isn't 81.]

 

The success is the area of the triangle bounded by the x-axis, the line y = -x + 6 and the line

y = -4x + 6.

The endpoints of this triangle are (1.5,0), (6,0) and (0,6).

 

Dividing the success by the possible will give you the probability.

 Jun 17, 2020

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