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I am reasking this question because i still don't have an answer. THank you for all the help that you have given me on my other questions. laugh

 

Let g(x) be a function piecewise defined as

\(g(x) = \left\{ \begin{array}{cl} -x & x\le 0, \\ 2x-41 & x>0. \end{array} \right.\)

If a is negative, find a so that \(g(g(g(10.5)))=g(g(g(a))).\)

 

 

THank you SO MUCH IN ADVANCE. ^_^

 Sep 17, 2019
 #1
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Step through it one g at a time

g(10.5) = 2(10.5)-41 = -20

g(-20) = 20

g(20) = 2(20) - 41 = -1     for the left hand side of the equation

 

g  (g g a) = -1      so    2x-41 = -1      2x= 40    x = 20

 

g   ga = 20        so     ga =       20 = 2x-41    2x= 61  x = 30.5

 

 

g(a) = 30.5      a = -30.5                    

 Sep 18, 2019
 #2
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OMG THANK YOU SO MUCH!!!! I have been stuck on this problem for a long time. laughlaughlaugh

 Sep 18, 2019
 #3
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You're welcome !   ( I wasn't signed in before when I posted) cheeky

 Sep 18, 2019

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