I am srry that I am reasking this.

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I am reasking this question because i still don't have an answer. THank you for all the help that you have given me on my other questions.

Let g(x) be a function piecewise defined as

\(g(x) = \left\{ \begin{array}{cl} -x & x\le 0, \\ 2x-41 & x>0. \end{array} \right.\)

If a is negative, find a so that \(g(g(g(10.5)))=g(g(g(a))).\)

THank you SO MUCH IN ADVANCE. ^_^

Guest Sep 17, 2019

Guest · Answer 1 · 2019-09-18T11:41:38

Step through it one g at a time

g(10.5) = 2(10.5)-41 = -20

g(-20) = 20

g(20) = 2(20) - 41 = -1 for the left hand side of the equation

g (g g a) = -1 so 2x-41 = -1 2x= 40 x = 20

g ga = 20 so ga = 20 = 2x-41 2x= 61 x = 30.5

g(a) = 30.5 a = -30.5

Guest · Answer 2 · 2019-09-18T11:44:27

OMG THANK YOU SO MUCH!!!! I have been stuck on this problem for a long time.

ElectricPavlov · Answer 3 · 2019-09-18T11:59:54

You're welcome ! ( I wasn't signed in before when I posted)