The nth term of a sequence is represented by 2n^4−15/6n^4+17 .

What is the limit of the the nth term as n becomes increasingly large?

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−13/23

1/3

3

The limit of the nth term does not exist.

TizzyT Feb 6, 2023

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Feb 6, 2023

edited by Guest Feb 6, 2023

edited by Guest Feb 6, 2023

edited by Guest Feb 6, 2023

edited by Guest Feb 6, 2023

#1**+1 **

2n^4−15/6n^4+17

\(\displaystyle \lim_{n\rightarrow \infty}\;\;\frac{2n^4−15}{6n^4+17}\\ \qquad \text{At an educated guess I would say 2/6 = 1/3}\\ \qquad \text{But I should be more mathematical about it}\\~\\ \text{divide through by n^4 top and bottom}\\~\\ \displaystyle \lim_{n\rightarrow \infty}\;\;\frac{2−\frac{15}{n^4}}{6+\frac{17}{n^4}}\\~\\ =\frac{2}{6}\\ =\frac{1}{3} \)

Melody Feb 7, 2023