I can't figure out the value of a- please help! (6y - 11)(6y + 11)=ay^2 - b)

Guest Feb 12, 2017

#1**+6 **

(6y - 11)(6y + 11)

All you need to do is "FOIL" this expression. That means multiply the __F__irst two terms of each factor together, multiply the __O__uter two terms of each factor together, multiply the __I__nner two terms of each factor together, and multiply the __L__ast two terms of each factor together. Then add each of those products together.

You can also think of this by saying,"The first term times the third and fourth term plus the second term times the third and fourth term." All this is doing is getting you to multiply each thing by every other thing.

So for this problem that will be:

= (6y)(6y) + (11)(6y) + (-11)(6y) + (-11)(11)

= 36y^{2} + 66y - 66y - 121

= 36y^{2} - 121

Now you can see that **a = 36**.

hectictar
Feb 12, 2017