+0  
 
-1
97
2
avatar

Hi, I posted this on the 15th and never got any help. Thanks for your help in advance:

 

(1) Degrees are not the only units we use to measure angles. We also use radians. Just as there are \(360^\circ\)  in a circle, there are \(2\pi\) radians in a circle. Compute \(\sin \frac{\pi}{6}\) where the angle \(\frac{\pi}{6}\)is in radians.

 

(2)Find the length AC, to two decimal places.

Use the texer here: https://artofproblemsolving.com/texer

Post code to find image in TeXeR:

[asy]
unitsize(2 cm);

pair A, B, C;

A = dir(40);
B = (0,0);
C = (3,0);

draw(A--B--C--cycle);

label("$A$", A, N);
label("$B$", B, SW);
label("$C$", C, SE);
label("$3$", (A + B)/2, NW);
label("$7$", (B + C)/2, S);
label("$50^\circ$", B + (0.5,0.15));
[/asy]

(3)Find the length BC, to two decimal places. 

 

Use the texer here: https://artofproblemsolving.com/texer

Post code to find image in TeXeR:

[asy]
unitsize(1 cm);

pair A, B, C;

A = 4*dir(71);
B = (0,0);
C = (5,0);

draw(A--B--C--cycle);

label("$A$", A, N);
label("$B$", B, SW);
label("$C$", C, SE);
label("$8$", (A + C)/2, NE);
label("$61^\circ$", A + (0.2,-0.8));
label("$43^\circ$", C + (-0.8,0.3));
[/asy]

 

NOTE, FOR SOME REASON, THE LATEX IN THE CODE IS RENDERING .... IF (and probably when) YOU PASTE TO FIND THE ANSWER, YOU MAY NEED TO FIGURE OUT *or you could just edit/take it from this post directly* WHAT THE ACTUAL CODING IS TO GET THE IMAGE CORRECTLY.... Thanks!

Thank you for your help in advance. laugh

 Nov 17, 2020
edited by Guest  Nov 17, 2020
 #1
avatar
0

(1) sin(pi/6) = sqrt(3)/2.

 

(2) AC = 4.7

 

(3) BC = 5.4

 Nov 17, 2020
 #2
avatar+112011 
+1

Please just one question per post.

 

Also, when reposting please include the link to the original post and ask people to answer on the original thread.

Thanks.

 Nov 18, 2020
edited by Melody  Nov 18, 2020
edited by Melody  Nov 18, 2020

47 Online Users

avatar
avatar
avatar
avatar