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I didn't get any help... Thanks.

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97
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Hi, I posted this on the 15th and never got any help. Thanks for your help in advance:

(1) Degrees are not the only units we use to measure angles. We also use radians. Just as there are $$360^\circ$$  in a circle, there are $$2\pi$$ radians in a circle. Compute $$\sin \frac{\pi}{6}$$ where the angle $$\frac{\pi}{6}$$is in radians.

(2)Find the length AC, to two decimal places.

Use the texer here: https://artofproblemsolving.com/texer

Post code to find image in TeXeR:

[asy]
unitsize(2 cm);

pair A, B, C;

A = dir(40);
B = (0,0);
C = (3,0);

draw(A--B--C--cycle);

label("$A$", A, N);
label("$B$", B, SW);
label("$C$", C, SE);
label("$3$", (A + B)/2, NW);
label("$7$", (B + C)/2, S);
label("$50^\circ$", B + (0.5,0.15));
[/asy]

(3)Find the length BC, to two decimal places.

Use the texer here: https://artofproblemsolving.com/texer

Post code to find image in TeXeR:

[asy]
unitsize(1 cm);

pair A, B, C;

A = 4*dir(71);
B = (0,0);
C = (5,0);

draw(A--B--C--cycle);

label("$A$", A, N);
label("$B$", B, SW);
label("$C$", C, SE);
label("$8$", (A + C)/2, NE);
label("$61^\circ$", A + (0.2,-0.8));
label("$43^\circ$", C + (-0.8,0.3));
[/asy]

NOTE, FOR SOME REASON, THE LATEX IN THE CODE IS RENDERING .... IF (and probably when) YOU PASTE TO FIND THE ANSWER, YOU MAY NEED TO FIGURE OUT *or you could just edit/take it from this post directly* WHAT THE ACTUAL CODING IS TO GET THE IMAGE CORRECTLY.... Thanks!

Nov 17, 2020
edited by Guest  Nov 17, 2020

#1
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(1) sin(pi/6) = sqrt(3)/2.

(2) AC = 4.7

(3) BC = 5.4

Nov 17, 2020
#2
+112011
+1

Please just one question per post.