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the junior class is renting a laser tag facility with a capacity of 325 people. the cost for the facility is $1200. the party must have at least 13 adult chaperones

a. if every student who attends shares the facility cost equally, what function models the cost per student C with respect to the number of students N who attend? what is the domain of the function? how many students must attend to make the cost per student no more than $7.50?

b. the class wants to promote the event by giving away 30 spots to students in a drawing. how does the model change? now how many paying students must attend so the cost for each is no more than $7.50?

 

someone explain how to solve this it confuses me beyond comprehension

OfficialBubbleTanks  Jan 26, 2018
 #1
avatar+94092 
+1

the junior class is renting a laser tag facility with a capacity of 325 people. the cost for the facility is $1200. the party must have at least 13 adult chaperones

a. if every student who attends shares the facility cost equally, what function models the cost per student C with respect to the number of students N who attend?

Cost per student = $1200/N  

 

what is the domain of the function?

\(domain: \;\;1\le N \le (312-additional\;adult\;chaperones)\qquad N\in Z\)

 

how many students must attend to make the cost per student no more than $7.50?

\(\frac{1200}{N}\le7.50\\ \frac{1200}{7.5}\le N\\ N \ge \frac{1200}{7.5}\\ N \ge 160 \)

 

b. the class wants to promote the event by giving away 30 spots to students in a drawing. how does the model change? now how many paying students must attend so the cost for each is no more than $7.50?

 

It doesn't change the number of PAYING students who must attend. It will still need to be 160 or more paying students. 

 

BUT N is not paying students, it is all students so the model does change.

 

Cost per attending student that is actually paying will be

\(Cost\;per\;paying\;student=\frac{1200}{N-30}\)

Melody  Jan 27, 2018
 #2
avatar+578 
+1

thank you so much! i have been stuck on this question for a few hours now.

OfficialBubbleTanks  Jan 27, 2018

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