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So, I got an assignment earlier, what I had to do was make an equation (probably the wrong wording, I'm really tired), that must contain a 1, a 2, a 3, and a 4, and only one of each number (also, exponents, square roots, and other math symbols are allowed, but are not required). That probably doesn't make sense, but I'll try to explain it.

We had to get them to result in answers between (and including) 0 to 20. Here are some examples

(1+4)-(2+3) = 0

1+2+3+4=10

4²+1³ = 17

4²+1+3 = 20

Again, I have already done this, I don't actually need help, I'm just curious as to what answers you can come up with.

Have an awesome rest of the day :-) ☺.

Edit: changed a minus to a plus, but I doubt anyone will see that.

Guest Aug 22, 2018

edited by
Guest
Aug 22, 2018

edited by Guest Aug 27, 2018

edited by Guest Aug 27, 2018

#1**+1 **

\(2+3-4-1=0\)

\(\frac{2-1}{4-3}=1\\ 4-3-1+2=2\\ \frac{2+1}{4-3}=3\\ \frac{4}{2}+3-1=4\\ 4+3-1*2=5\\ \frac{4}{2}+1+3=6\\ (4+3)(2-1)=7\\ (3-1)^2+4=8\\ 1*2+3+4=9\\ 1+2+3+4=10\\ 2*3+4+1=11\\ 2^3+4*1=12\\ 2^3+4+1=13\\ 2*(3+4)*1=14\\ 3*(4+2-1)=15\\ 4*(3+2-1)=16\\ 3*(2+4)-1=17\\ 3*(2+4)*1=18\\ (2+3)*4-1=19\\ 1*(2+3)*4=20\)

.Melody Aug 22, 2018