+0  
 
+1
166
4
avatar

Thank you to anyone who answers

 Nov 10, 2019
 #1
avatar
0

All negative x satisfy the inequality, so the solution is (-infty,0).

 Nov 10, 2019
 #2
avatar+21773 
0

Either the (x-2)^2  or the (x+1)  needs to be negative (but not both) for this equation to be true

    However, (x-2)^2  is always POSITIVE (or zero)

      so the (x+1) portion must be negative

            (x+1) <0

              x <-1

(-inf, -1)

 

Disregard this answer.....  I didn't see the leading 'x' of the equation !!!!!

 Nov 10, 2019
edited by ElectricPavlov  Nov 10, 2019
edited by ElectricPavlov  Nov 10, 2019
 #3
avatar+11672 
+1

This is my answer:

laugh

 Nov 10, 2019
 #4
avatar+21773 
+1

(x+2)^2 is always positive or zero, so it cannot make the answer <0

 

so either x+1   or x   (but not BOTH) has to be less than zero for this equation to be true

 

x<0       or     x+1<0

x<0       or     x<-1           <======    so the only interval ONE of these is less than zero is   (-1,0)

 Nov 10, 2019

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