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I don't see how you can find the values from just the info given

Mellie  Apr 28, 2017
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4+0 Answers

 #1
avatar+4777 
+2

Let's call the unknown scale factor "s'"..

 

1s + 2s + 4s + 5s = 360º

 

Solve for s.

12s = 360º

s = 30º

 

So...

a. m arc PQ = 1s = 1(30º) = 30º

 

b. m arc QR = 2s = 2(30º) = 60º

 

c. m arc RS = 4s = 4(30º) = 120º

 

d. m arc SP = 5s = 5(30º) = 150º

 

e. m∠S = (1/2) * (m arc PQ + m arc QR) = (1/2) * (30 + 60) = 45º

 

f. m∠Q = (1/2) * (m arc RS + m arc SP) = (1/2) * (120 + 150) = 135º

 

g. m∠R = (1/2) * (m arc PQ + m arc SP) = (1/2) * (30 + 150) = 90º

 

h. m∠P = (1/2) * (m arc RS + m arc QR) = (1/2) * (120 + 60) = 90º

 

*edit* added ºs :)

hectictar  Apr 28, 2017
edited by hectictar  Apr 28, 2017
 #2
avatar+90633 
+1

Hi Mellie :)

I am really not convinced Hectictar,  

Your angles are correct but I do not think that there is enough info to give the arc lengths.

Your s relates to angles subtended from the centre.  The 360 is 360 degrees. It is not related to the length of the circumference.

 

 \(\text{You could say that } arc {PQ}= \dfrac{\pi r} {6}\\ \text{and } \qquad \qquad \qquad arc \;{QR}= \dfrac{2\pi r} {6}\\ \text{and } \qquad \qquad \qquad arc \;{RS}= \dfrac{4\pi r} {6}\\ \text{and } \qquad \qquad \qquad arc \; {SP}= \dfrac{5\pi r} {6}\\ \)

 

 

Where  r is the radius but I do not see how you can give exact values for these.  :/

Melody  Apr 28, 2017
 #3
avatar+4777 
+2

I might be wrong on this.... but I think the question wants the measure of the arc which is the measure of the central angle that intercepts the arc. I agree with you that the lengths of the arcs can't be found with the given info

hectictar  Apr 28, 2017
 #4
avatar+90633 
+1

Yes you are most likely correct Hectictar  laugh  

I am not sure if there is any specific meaning to those symbols.  I did not think of your interpretation  :)

Melody  Apr 28, 2017

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