+92 Ok. So, to do this problem, we first need to find the angle measure of x.
The problem says that \(m\angle PKS = 3x + 10\) and also \(m\angle SKR = x - 12, m\angle RKP = 62\). We know that the latter two angles sum up to make \(\angle PKS\), so we get the equation:
\((x-12)+62=3x+10\)
From this, we can solve for x (I'm going to spare you the details of that, since you probably already know how).
\(x=20\)
Now, since we have the value of x, all we have to do is plug it into \(m\angle PKS = 3x + 10\) and \(m\angle SKR = x - 12\), getting:
\(m\angle PKS = 70\), \(m\angle SKR = 8\)
I hope this helped! 
NOTE: The image was probably not to scale and all that, so this answer will seem incorrect. But if you check it, it will work.
