Ok. So, to do this problem, we first need to find the angle measure of x.
The problem says that \(m\angle PKS = 3x + 10\) and also \(m\angle SKR = x - 12, m\angle RKP = 62\). We know that the latter two angles sum up to make \(\angle PKS\), so we get the equation:
From this, we can solve for x (I'm going to spare you the details of that, since you probably already know how).
Now, since we have the value of x, all we have to do is plug it into \(m\angle PKS = 3x + 10\) and \(m\angle SKR = x - 12\), getting:
\(m\angle PKS = 70\), \(m\angle SKR = 8\)
I hope this helped!
NOTE: The image was probably not to scale and all that, so this answer will seem incorrect. But if you check it, it will work.