point H is located at (-7,5) where is h after a 270 degree clockwise rotation
+36916 It will go from Quadrant 2 to Quadrant 3 and will be -5, -7
"I don't do math" better learn 'to do' math or " I don't do math" will never get far in this world. 
and I won't get much further if I make MISTAKES at math !! Corrected my typo
+128475 A 270° clockwise rotation is the same as a -90° counter-clockwise rotation
Let ( x, y) be the original point = ( -7, 5)
A 90° counter-clockwise rotation gives us (-y, x) = (-5, -7)
Here's the graph :
+26367 point H is located at (-7,5) where is h after a 270 degree clockwise rotation
Let \(270^\circ\) clockwise rotation = \(90^\circ\) counter clockwise rotation
\(\begin{array}{|lrcll|} \hline & && \text{complex} \\ \hline (-7,\ 5) \rightarrow & && ( -7+5i) \\ & && ( -7+5i)\times i & \times i ~(\text{ $90^\circ$ counter clockwise rotation}) \\ & &=&-7i+5i\times i \\ & &=&-7i+5i^2 \quad i^2 = -1 \\ & &=&-7i-5\\ (-5,\ -7) \leftarrow & &=&(-5-7i)\\ \hline \end{array} \)
