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# i dont know how to do this

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Let f(x)=3x^4-7x^3+2x^2-bx+1. For what value of b is f(1)=1?

May 27, 2020

#1
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3x^4-7x^3+2x^2-bx+1      put in '1' for 'x' to find  f(1)    and it has to = 1

3 (14) - 7(13) + 2 (12) - b(1) + 1   = 1         I think you should be able to take it from here !

*** edited ****     Thanx, Alan !

May 27, 2020
edited by ElectricPavlov  May 27, 2020
#2
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Let me try...

I simplified it to get $$x=\frac{-2}{b}$$ and $$b ≠ 0$$...

Guest May 27, 2020
#3
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I think EP meant to write:

3 (14) - 7(13) + 2 (12) - b(1) + 1   = 1      All the x's should be replaced by 1's.  Now find b.

Alan  May 27, 2020
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OHHHHH okay thank you!!!

Guest May 27, 2020