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Let f(x)=3x^4-7x^3+2x^2-bx+1. For what value of b is f(1)=1?

 May 27, 2020
 #1
avatar+26620 
+2

3x^4-7x^3+2x^2-bx+1      put in '1' for 'x' to find  f(1)    and it has to = 1

 

3 (14) - 7(13) + 2 (12) - b(1) + 1   = 1         I think you should be able to take it from here !   cheeky

 

*** edited ****     Thanx, Alan ! 

 May 27, 2020
edited by ElectricPavlov  May 27, 2020
 #2
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Let me try...

 

I simplified it to get \(x=\frac{-2}{b}\) and \(b ≠ 0\)...

Guest May 27, 2020
 #3
avatar+30913 
+1

I think EP meant to write:

 

3 (14) - 7(13) + 2 (12) - b(1) + 1   = 1      All the x's should be replaced by 1's.  Now find b.

Alan  May 27, 2020
 #4
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OHHHHH okay thank you!!!

Guest May 27, 2020

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