i dont know how to solve can someone help me?

Hi Sabi92, 

Welcome to the Web2 forum   

This is a very strange place to put your question.

Just put it on a new post next time.  :)

I really like that fact that you have had a go at it yourself and that you have shown us your work :)

$$\\a(2b^2-c)+b(c-2b^2)$$

what you need to notice here is that the brackets contain the same things except the signs are different.  

I am going to look at the second bracket. I could just as easily chosen the first bracket :)

$$c-2b^2 = -1(-c+2b^2)=-1(2b^2-c)$$

so

$$+b(c-2b^2)=+b*-1(2b^2-c) = -b(2b^2-c)$$

so

$$\\a(2b^2-c)+b(c-2b^2)\\\\ =a(2b^2-c)-b(-c+2b^2)\\\\ =a\textcolor[rgb]{0,1,0}{(2b^2-c)}-b\textcolor[rgb]{0,1,0}{(2b^2-c)}\\\\ $Now you have a lots of the green stuff minus b lots of the green stuff$\\\\ $which equals (a-b) lots of the green stuff$\\\\ =(a-b)(2b^2-c)\\\\$$

6*x=x*x

x must be 6    

no i have these answers x=0 and x=3 but i dont the way how to solve it

 i dont know how to solve can someone help me

6x=x^2

x=?

$$\small{\text{ $ \begin{array}{rcl} 6x & = & x^2 \\ x^2 - 6x &=& 0 \\ \underbrace{x}_{=0}(\underbrace{x-6}_{=0}) &=& 0 \\ \end{array} $ }}$$

1. x = 0

2. x-6 = 0 | +6

    x    = 6

thank you very much:)!

Very nice Heureka :)

oops im sorry i wrote a wrong question the real question is 

6x=2x^2

x=?

so how can i solve it? 

 i dont know how to solve can someone help me

6x=2x^2

x=?

$$\small{\text{ $ \begin{array}{rcl} 6x & = & 2x^2 \\ 2x^2 - 6x &=& 0 \\ \underbrace{x}_{=0}(\underbrace{2x-6}_{=0}) &=& 0 \\ \end{array} $ }}$$

1. x = 0

2. 2x-6 = 0 | +6

    2x    = 6 | : 2

     x    = 6 /2

     x    = 3

It is similar to what Heureka did.

$$\\6x=2x^2\\ 3x^2-6x=0\\ 3x(x-2)=0$$

you should be able to finish it :)

ok thnk you but its 2x(x-3)=0

i need to do a factorization but i dont get the right answer.help please.

a(2b^2-c)+b(c-2b^2)

that's what i did:

2ab^2-ac+bc-2b^3=a(2b^2-c)+b(c-2b^2)

now what?