+0  
 
0
97
3
avatar+383 

I dont understand hou to do this.... help

 

 

https://snag.gy/pgMu6y.jpg

hoiuu  Sep 19, 2018

Best Answer 

 #2
avatar+3446 
+3

Well, I'll solve one of them.

1. \(6x+4x-6=24+9x, 10x-6=24+9x, x=30\), so one solution.

Remember infinite solutions, 0=0, etc.

tertre  Sep 19, 2018
 #1
avatar+94105 
+1

Don't be so lazy. TYPE just one of these questions in, lean from the answer, and do the others yourself.

You won't learn anything from copying all of other peoples answers. 

Melody  Sep 19, 2018
 #2
avatar+3446 
+3
Best Answer

Well, I'll solve one of them.

1. \(6x+4x-6=24+9x, 10x-6=24+9x, x=30\), so one solution.

Remember infinite solutions, 0=0, etc.

tertre  Sep 19, 2018
 #3
avatar+92674 
+3

b) 25 - 4x  = 15- 3x + 10 - x   simplify

 

25 - 4x = 25 - 4x

 

Same expressions on both sides will give us infinite solutions for  x

 

 c) 4x + 8  = 2x + 7 + 2x  - 20    simplify

 

4x + 8 =  4x - 13       subtract 4x from both sides

 

8  = -13     absurd answer  means that no solutions exist.....

 

cool cool cool

CPhill  Sep 20, 2018
edited by CPhill  Sep 20, 2018
edited by CPhill  Sep 20, 2018

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