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# I dont understand hou to do this.... help

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I dont understand hou to do this.... help

https://snag.gy/pgMu6y.jpg

Sep 19, 2018

#2
+3

Well, I'll solve one of them.

1. \(6x+4x-6=24+9x, 10x-6=24+9x, x=30\), so one solution.

Remember infinite solutions, 0=0, etc.

Sep 19, 2018

#1
+1

Don't be so lazy. TYPE just one of these questions in, lean from the answer, and do the others yourself.

You won't learn anything from copying all of other peoples answers.

Sep 19, 2018
#2
+3

Well, I'll solve one of them.

1. \(6x+4x-6=24+9x, 10x-6=24+9x, x=30\), so one solution.

Remember infinite solutions, 0=0, etc.

tertre Sep 19, 2018
#3
+3

b) 25 - 4x  = 15- 3x + 10 - x   simplify

25 - 4x = 25 - 4x

Same expressions on both sides will give us infinite solutions for  x

c) 4x + 8  = 2x + 7 + 2x  - 20    simplify

4x + 8 =  4x - 13       subtract 4x from both sides

8  = -13     absurd answer  means that no solutions exist.....   Sep 20, 2018
edited by CPhill  Sep 20, 2018
edited by CPhill  Sep 20, 2018