+0  
 
+1
97
8
avatar+89 

Find the area of the triangle below. 

Isn't a triangle's area just supposed to BH/2. I dunno if I'm overthinking this or not so I just wanted to hear what y'all think?


 May 28, 2021
 #1
avatar+34340 
+1

You don't have the height of the triangle.....you only have the side lengths

 are you familiar with Heron's formula ?   Use it to find the area of a triangle with only the 3 side lengths

 May 28, 2021
 #2
avatar+89 
0

I am. Let me do it real quick

tmatthews  May 28, 2021
 #3
avatar+89 
+1

I got 65. Is that correct?

tmatthews  May 28, 2021
 #4
avatar+34340 
+1

I think it is 60.....but here is another way.....it is an isocoles triangle ....break it into two right triangles then 1/2 b * h    for the two triangles and add them

 

ElectricPavlov  May 28, 2021
 #5
avatar+89 
0

How did you find the height(5)?

tmatthews  May 28, 2021
edited by tmatthews  May 28, 2021
 #6
avatar+20 
+1

Pyhatgorean Therom,

13^2 = 12^2 + x^2

169 = 144+x^2

x^2 = 25

x = 5

BuilderBoi  May 28, 2021
 #7
avatar+89 
0

Thanks! I totally overlooked that.

tmatthews  May 28, 2021
 #8
avatar+1486 
+3

A = 12[sqrt(132 - 122)]

 May 28, 2021

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