+259 Well since u only said its a triangle i will think its a right triangle: (otherwise i got no idea)
Since you only have one side given a and b will always variety.
To get a fixed size we can use the pythagoras:
a^2 + b^2 = c^2
a^2 + b^2 = 14^2. I -a^2
b^2 = 196 - a^2
and
a^2 = 196 - b^2
Example:
U want the size for b when a is 4:
b^2 = 196 - 4^2
b = 13.42
+259 Well since u only said its a triangle i will think its a right triangle: (otherwise i got no idea)
Since you only have one side given a and b will always variety.
To get a fixed size we can use the pythagoras:
a^2 + b^2 = c^2
a^2 + b^2 = 14^2. I -a^2
b^2 = 196 - a^2
and
a^2 = 196 - b^2
Example:
U want the size for b when a is 4:
b^2 = 196 - 4^2
b = 13.42
+12530
The Pythagorean numbers are: 3, 4 and 5
The hypotenuse is 14
14 divided by 5 is 2.8
3 times 2.8 is 8.4
4 times 2.8 is 11.2
8,42 + 11,22 = 196
70,56 + 125,44 = 196
+37146 TOOOOOO many solutions to this problem without more infrmation......assuming it is a Right Triangle, you can just pick ONE side and then compute the other .....infinitely
Example: Hypotenuse = 14 let's pick side 'a' as 3.6 then side 'b'
would be sqrt(14^2 -3.6^2) = 13.52
or if you pick side 'a' as 8.1 then 'b' would be
sqrt(14^2 -8.1^2) =11.41
etc etc etc
