+0  
 
+3
765
4
avatar+839 

I feel like this should be easy but I dont get how to set up the equation.

 Jul 13, 2014

Best Answer 

 #1
avatar+124676 
+13

Note Rose98, that J is located at (4,4). It has the same y coordinate that L does, and L is located on the y axis. So L must be located at (0,4). For a analogous reason, K's coordinates must be (4,0). So you can use the distance formula to find the distance between L and K.

However, we have a square here because JK =JL = 4 = the side length.

And the diagonal of a square is just the side length times √2.

So, 4*√2  = the diagonal length.    This is easier than using the distance formula, IMHO.

Does that help??

 

 Jul 13, 2014
 #1
avatar+124676 
+13
Best Answer

Note Rose98, that J is located at (4,4). It has the same y coordinate that L does, and L is located on the y axis. So L must be located at (0,4). For a analogous reason, K's coordinates must be (4,0). So you can use the distance formula to find the distance between L and K.

However, we have a square here because JK =JL = 4 = the side length.

And the diagonal of a square is just the side length times √2.

So, 4*√2  = the diagonal length.    This is easier than using the distance formula, IMHO.

Does that help??

 

CPhill Jul 13, 2014
 #2
avatar+839 
+3

Your so amazing.  Thank you!  That really helps :)

 Jul 13, 2014
 #3
avatar+8260 
0

Is this grade 10?

  

 Jul 13, 2014
 #4
avatar+839 
0

Yuppers :)

 Jul 13, 2014

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