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# I feel like this should be easy but I dont get how to set up the equation.

+3
868
4
+839

I feel like this should be easy but I dont get how to set up the equation.

Jul 13, 2014

### Best Answer

#1
+125697
+13

Note Rose98, that J is located at (4,4). It has the same y coordinate that L does, and L is located on the y axis. So L must be located at (0,4). For a analogous reason, K's coordinates must be (4,0). So you can use the distance formula to find the distance between L and K.

However, we have a square here because JK =JL = 4 = the side length.

And the diagonal of a square is just the side length times √2.

So, 4*√2  = the diagonal length.    This is easier than using the distance formula, IMHO.

Does that help??

Jul 13, 2014

### 4+0 Answers

#1
+125697
+13
Best Answer

Note Rose98, that J is located at (4,4). It has the same y coordinate that L does, and L is located on the y axis. So L must be located at (0,4). For a analogous reason, K's coordinates must be (4,0). So you can use the distance formula to find the distance between L and K.

However, we have a square here because JK =JL = 4 = the side length.

And the diagonal of a square is just the side length times √2.

So, 4*√2  = the diagonal length.    This is easier than using the distance formula, IMHO.

Does that help??

CPhill Jul 13, 2014
#2
+839
+3

Your so amazing.  Thank you!  That really helps :)

Jul 13, 2014
#3
+8261
0

Is this grade 10?

Jul 13, 2014
#4
+839
0

Yuppers :)

Jul 13, 2014