The sum of a list of seven positive integers is 42. The mean, median and mode are consecutive integers,
in some order. What is the largest possible integer in the list?
any tips or can somebody guide me through this :00??
Here's my attempt !!!
Mean = sum / number of integers = 42/7 = 6
We would like to make the mode (and median) as small as possible.....
Let the mode = 4 and the median = 5
And we want the first integer to be as small as possible = 1
1 4 4 5 6 7 15
The mode = 4
The median = 5
The average = 6
I get 15 as the largest value.......???
Maybe CU has a better answer !!!
I don't know because we know that 6 is the mean so then that would leave us with 4 and 5 or 5 and 4 for the mode and the median.
Yes if we let the mode equal to 4 and the median as 5 then the largest possible value would be 15
however if we let 5 equal to the mode and 4 as the median then wouldn't it be 22??
I'm confused because I have two values now, and I don't know what to do.
LOL I went on to compose one of the longest explanations I ever did.
I got as close to you, and when I realized my answer was falling apart, I just deleted the entire thing and waited for someone else to explain XD.
Let's see if we can get a larger answer.....
Mean = 6
Mode = 5
Median = 4
1 2 3 4 5 5 22
Yes!!!.....you are correct, Nirvana.....we CAN do better than 15 !!!!