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# i forgot how to do these :o

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The sum of a list of seven positive integers is 42. The mean, median and mode are consecutive integers,
in some order. What is the largest possible integer in the list?

any tips or can somebody guide me through this :00??
thanks

Sep 26, 2019

#1
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Here's my attempt  !!!

Mean  =   sum / number of integers  =  42/7  =    6

We would like to make the mode  (and median) as small as possible.....

Let the mode = 4  and the median   = 5

And we want the first  integer to be as small as possible  = 1

1  4  4  5  6  7 15

The mode  = 4

The median  = 5

The average = 6

I get 15  as the largest value.......???

Maybe CU  has a better answer    !!!

Sep 26, 2019
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Thank you CPhill!! :))

Nirvana  Sep 26, 2019
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I don't know because we know that 6 is the mean so then that would leave us with 4 and 5 or 5 and 4 for the mode and the median.

Yes if we let the mode equal to 4 and the median as 5 then the largest possible value would be 15
however if we let 5 equal to the mode and 4 as the median then wouldn't it be 22??

I'm confused because I have two values now, and I don't know what to do.

Nirvana  Sep 26, 2019
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LOL I went on to compose one of the longest explanations I ever did.

I got as close to you, and when I realized my answer was falling apart, I just deleted the entire thing and waited for someone else to explain XD.

CalculatorUser  Sep 26, 2019
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oh lol :')

so let me ask you this....
would it have two solutions or-

Nirvana  Sep 26, 2019
edited by Nirvana  Sep 26, 2019
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Let's see if we can get a larger answer.....

Mean  = 6

Mode = 5

Median = 4

1  2   3  4  5  5  22

Yes!!!.....you are correct,  Nirvana.....we CAN do better than 15  !!!!

Good, job!!!!

Sep 26, 2019
edited by CPhill  Sep 26, 2019
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yay!!!!!

thank you so much CPhill!!! :)

Nirvana  Sep 26, 2019
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Well.....YOU really found the correct answer....not ME!!!

LOL!!!

CPhill  Sep 26, 2019
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awe well, you still helped me so i really appreciate it! :)

Nirvana  Sep 26, 2019
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