#1**+1 **

.955 not .995

B 7000 = 8500 (.955)^t solve for t (the number of years past 2010)

ElectricPavlov
Jun 8, 2018

#2**+1 **

7000 = 8500(.955)^t divide both sides by 8500

7000/8500 = .955^t

7000/8500 = .955^t take the log of both sides

log (7000/8500) = log (.955)^t and we can write

log (7000/8500) = t * log (.955) divide both sides by log(.955)

log (7000/8500) / log (.955) = t ≈ 4.2 years after 2010 = 2014

CPhill
Jun 8, 2018

#3**+1 **

I could be overthinking this, but wouldn't 4.2 years after 2010 be 2015?

4 years after 2010 would certainly land in 2014, but the extra .2 years would spill over into the year 2015.

TheXSquaredFactor
Jun 9, 2018