I have attempted to solve this problem numerous of times can someone please help me? It is asking me to solve the equality.

x²-2x-4≥0

first solve   $$x^2-2x-4=0$$

NO factors are jusmping out at me so you couold solve it usingthe quadratic formula

a=1,  b=-2 and c = -4

http://www.youtube.com/watch?v=O8ezDEk3qCg 

I'm going to try and get this answer using the the site calc

$${\frac{\left({\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{16}}}}\right)}{{\mathtt{2}}}} = {\mathtt{3.236\: \!067\: \!977\: \!499\: \!789\: \!7}}$$

$${\frac{\left({\mathtt{2}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{16}}}}\right)}{{\mathtt{2}}}} = -{\mathtt{1.236\: \!067\: \!977\: \!499\: \!789\: \!7}}$$

so the roots are approx  x=3.2 and x=-1.2

$$y=x^2-2x-4$$     is a concave up (Because the number in fornto of the x^2 is positive) parabola (x^2)

If you scketch it on a peice of paper you will see that y is above 0 at the 2 endss so

$$x\le -1.2\qquad and\qquad x \ge 3.2$$    correct to one dec place.    

 I think that is all ok,  If you need more explanation then aske for it.