The position of a particle is given by the parametric equations

as t ranges over all real numbers.

x=3+2sin(2t)

y=4+2cos(2t)

The particle visits the points P, Q, R, S at times -pi/6, 0, pi/3, pi/2 in some order. Order the points

so that the particle is at the first point at time -pi/6, at the second point at time 0, at the third point at time pi/3, and at the last point at time pi/2.

I would really appreciate an answer as soon as possible. Thanks!

THIS IS JUST TO GET THE ATTENTION OF POTENTIAL ANSWER HOLDERS IF YOU KNOW HOW TO DO THIS PLEASE HELP THANKS!

JRFPLSHelp Jul 26, 2024

#1**+1 **

P

x = 3 + 2sin (2 *-pi6) = 3 + 2 sin (-pi/3) = 3 + 2 *(-sqrt 3 / 2) = 3 - sqrt 3

y = 4 + 2cos (2 *-pi/6) = 4 + 2 cos (-pi/3) = 4 + 2(1/2) = 5

Q

x = 3 + 2sin (2*0) = 3 + 2(0) = 3

y = 4 + 2cos (2*0) = 4 + 2 (1) = 6

R

x= 3 + 2sin (2 *pi/3) = 3 + 2 sin (2pi/3) = 3 + 2 (sqrt 3 / 2) = 3 + sqrt 3

y = 4 + 2cos(2 *pi/3) = 4 + 2 (-1/2) = 3

S

x = 3 + 2sin (2 *pi/2) = 3 + 2 (0) = 3

y = 4 + 2cos (2 *pi/2) = 4 + 2(-1) = 2

CPhill Jul 27, 2024